3x^2+5x-6+x^2-5x-7=9x^2+10x-7

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Solution for 3x^2+5x-6+x^2-5x-7=9x^2+10x-7 equation: 



3x^2+5x-6+x^2-5x-7=9x^2+10x-7

We move all terms to the left:

3x^2+5x-6+x^2-5x-7-(9x^2+10x-7)=0

We add all the numbers together, and all the variables

4x^2-(9x^2+10x-7)-13=0

We get rid of parentheses

4x^2-9x^2-10x+7-13=0

We add all the numbers together, and all the variables

-5x^2-10x-6=0

a = -5; b = -10; c = -6;
Δ = b2-4ac
Δ = -102-4·(-5)·(-6)
Δ = -20
Delta is less than zero, so there is no solution for the equation

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